to require every NaN to be eqv? to every other NaN, but several people have already expressed their opposition to such a requirement, and I would like to make it clear that I too oppose it. Will [1] http://lists.r6rs.org/pipermail/r6rs-discuss/2007-June/002944.html [2] http://lists.r6rs.org/pipermail/r6rs-discuss/2007-June/003037.html