[r6rs-discuss] incorrect result in example for expt

[Chongkai Zhu]

Mathematically, limit (expt x y), x->0,  y->0 is undefined, in the same 
sense that limit (/ x y), x->0,  y->0 is undefined.

Chongkai

Abdulaziz Ghuloum wrote:
>
> On Aug 10, 2008, at 8:15 PM, Chongkai Zhu wrote:
>
>> I can't understand why (expt 0 0) should be 1. Would anyone explain?
>
> Because 1 is the identity of the multiplication operation.